Solution URL
https://leetcode.com/submissions/detail/413543446/
代码
class Solution {
public int nthUglyNumber(int n) {
//https://leetcode-cn.com/problems/ugly-number-ii/solution/zui-rong-yi-li-jie-de-si-lu-by-linzb-2/
int[] ele = new int[]{2,3,5};
long[] res = new long[n];
res[0] = 1;
PriorityQueue<Long> pq = new PriorityQueue<>();
for(int i = 0; i < res.length; i++){
for(int j = 0; j < ele.length; j++){
if(!pq.contains((long)res[i] * ele[j])){
pq.add((long)res[i] * ele[j]);
}
}
//将优先队列头元素加入res结果集中
if(i + 1 < res.length){
res[i + 1] = pq.poll();
}
}
return (int)res[n - 1];
}
}