Solution URL
https://leetcode.com/submissions/detail/412410037/
代码
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
* // Constructor initializes an empty nested list.
* public NestedInteger();
*
* // Constructor initializes a single integer.
* public NestedInteger(int value);
*
* // @return true if this NestedInteger holds a single integer, rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds, if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // Set this NestedInteger to hold a single integer.
* public void setInteger(int value);
*
* // Set this NestedInteger to hold a nested list and adds a nested integer to it.
* public void add(NestedInteger ni);
*
* // @return the nested list that this NestedInteger holds, if it holds a nested list
* // Return null if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
class Solution {
//ans: https://leetcode-cn.com/problems/mini-parser/solution/java-di-gui-jiu-vansla-by-leetcoder-youzg/
private char[] c;
private int idx = 0;
public NestedInteger deserialize(String s) {
//corner case
if(s == null || s.length() == 0) return null;
//若第一个不是 [
c = s.toCharArray();
if(c[0] != '['){
return new NestedInteger(Integer.valueOf(s));
}else{//若第一个是 [
return helper();
}
}
public NestedInteger helper(){
NestedInteger nest = new NestedInteger();
int sign = 1;
int num = 0;
while(idx < c.length - 1){
idx++;
//若为[,则递归
if(c[idx] == '['){
nest.add(helper());
}else if(c[idx] == '-'){
sign = -1;
}else if(c[idx] == ','){
continue;
}else if(c[idx] == ']'){
return nest;
}else{
num = num * 10 + sign * (c[idx] - '0');
if(c[idx+1] == ',' || c[idx+1] == ']'){
nest.add(new NestedInteger(num));
sign = 1;
num = 0;
}
}
}
return null;
}
}